m.aletriby
06-13-2010, 08:13 PM
Greetings and welcome.....
four control problems
-----------------
pb(3.14)
take vh=vref
for ex. qa=55, vref=.15root(55)
hyst.=1%vref, =.01*vref
hyst.=vh-vl, get vl
now u have vh, vl design the comparator for qa
do the same for all other criticals
then AND all the o/ps
------------------------------------
pb(3.37)
the range of R is [2350,3570]
and resolution is 1.25ohm
so no. of states =3570-2350/1.25=976
so we need 10 bit ADC (1024)states
Assume vr of the ADC say vr=5
now Vadc ranges from [0,5] as the resistance change
design the opAmp ct.
------------------------------------
pb(s2.1)
when weight=0, Rw=119
then calc. Rz to null the bridge
(b)as Rz vary from 0 to 200 get Rw that will null the bridge this is min and max of Rw
(c)use the equation of deltaV of the bridge
---------------------------------------------------------
pb(s2.2)
weight=[o,299]
Rw=[119,127]
deltaV=[0,v]
v is calc. in step (c)
Vr=kv
Vr=2.99
find k
(b)self
four control problems
-----------------
pb(3.14)
take vh=vref
for ex. qa=55, vref=.15root(55)
hyst.=1%vref, =.01*vref
hyst.=vh-vl, get vl
now u have vh, vl design the comparator for qa
do the same for all other criticals
then AND all the o/ps
------------------------------------
pb(3.37)
the range of R is [2350,3570]
and resolution is 1.25ohm
so no. of states =3570-2350/1.25=976
so we need 10 bit ADC (1024)states
Assume vr of the ADC say vr=5
now Vadc ranges from [0,5] as the resistance change
design the opAmp ct.
------------------------------------
pb(s2.1)
when weight=0, Rw=119
then calc. Rz to null the bridge
(b)as Rz vary from 0 to 200 get Rw that will null the bridge this is min and max of Rw
(c)use the equation of deltaV of the bridge
---------------------------------------------------------
pb(s2.2)
weight=[o,299]
Rw=[119,127]
deltaV=[0,v]
v is calc. in step (c)
Vr=kv
Vr=2.99
find k
(b)self